Why wouldn't heating a hydrate in a crucible to calculate percentage of water be appropriate for all hydrates?

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2007-10-28 10:37:36 · 2 answers · asked by ori_culumn 1 in Science & Mathematics ➔ Chemistry

Because some of them, like CuCl2*2H2O, might be converted to cupric oxide.

CuCl2*2H2O(s) + heat ===> CuO(s) + 2HCl(g) + H2O(g)

2007-10-28 10:45:52 · answer #1 · answered by steve_geo1 7 · 0⤊ 0⤋

Some hydrates would completely decompose instead of becoming anhydrous.

2007-10-28 10:41:44 · answer #2 · answered by ChemTeam 7 · 0⤊ 0⤋