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What Volume of 0.750 M Na3PO4 is required to precipitate all the lead(II) ions from 130.0 mL of 0.250 M Pb(NO3)2?

2007-10-28 10:31:10 · 1 answers · asked by Anonymous in Science & Mathematics Chemistry

1 answers

The first thing you need to do is to write out a balanced chemical equation (net ionic equation is best) for this precipitation.

Once you have the balanced equation (you'll need to know the coefficients of the Pb2+ and PO4 ions), calculate the moles of Pb2+ ions in the initial solution.

Then, use that to calculate how many moles of phosphate ions you'll need.

Finally, use the moles of phosphate ions and the concentration of the sodium phosphate to calculate the volume of that solution.

This kind of problem will confront you continuously in chemistry classes. You need to work with them until they are easy for you to do.

2007-10-28 10:40:56 · answer #1 · answered by hcbiochem 7 · 0 0

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