a piece of gold, mass 35.0 grams, absorbs 185 joules of heat energy when its temperature increases by 41 degrees C. What is the specific heat of gold?
2007-10-28 10:04:27 · 3 answers · asked by Chrishonda Alston 3 in Science & Mathematics ➔ Chemistry
the formula is q=m x C x deltaT
where q is heat, m is mass, C is specific heat, and delta t is the difference in temperature
so,
185= 35 x C x 41
185= 1435C
.129= C
the specific heat of gold is .129 J/g x degrees Celsius
2007-10-28 10:16:02 · answer #1 · answered by lizochkabst 2 · 0⤊ 0⤋
Q = mcDeltaT
c = specific heat capacity (To be found)
Q = heat change
m = mass (in Kg)
Delta T = difference in temperature.
c = Q/mDeltaT
c = 185J/0.035Kg x 41K = 128.91 J Kg^-1 K^-1
This value, (128.91 J Kg^-1 K^-1) compares favourably with the book value of 130J Kg^-1 K^-1, per McGlashan, 'Chemistry Data Book' ISBN 0 7195 3951 X.
2007-10-28 17:17:41 · answer #2 · answered by lenpol7 7 · 0⤊ 0⤋
185 J /(41 deg C x 35.0g) = 0.129 J/ g degC
2007-10-28 17:17:40 · answer #3 · answered by skipper 7 · 0⤊ 0⤋