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Calculate the moles of oxygen in the tank.

a) 383
b) 4.57
c) 0.0505
d) 0.383
e) 0.00378

thanks

2007-10-28 09:27:31 · 2 answers · asked by bocabrunette714 1 in Science & Mathematics Chemistry

2 answers

For an ideal gas PV=nRT
where
P = pressure (in atm)
V = volume (in L)
n = # of moles of gas
R = ideal gas law constant (0.082 atm-L/mol-K)
T = temperature (in Kelvin or degC+273.15)

so

n = PV/RT
= (75 atm)(0.125 L)/[(0.082 atm-L/mol-K)(298.15 K)]
= 0.383 mol

Please try to study first for your next homework.

2007-10-28 09:43:25 · answer #1 · answered by Mark 2 · 0 0

Just use the ideal gas law: PV=nRT and solve for n. Be sure that your temperature is converted to K, and your volume to L. R will be 0.0821 L atm/mol K

2007-10-28 16:37:04 · answer #2 · answered by hcbiochem 7 · 0 0

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