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self explanitory please give your answers with working and try and keep it as simple as possible

2007-10-28 08:17:44 · 2 answers · asked by zush 1 in Science & Mathematics Mathematics

2 answers

Pascal is right. If you want to try to involve logs this is what happens...

let y =x^a
Take natural logs of both sides...

lny = alnx

Differentate

(1/y)dy/dx = a/x

ie dy/dx = ay/x

But y=x^a

so dy/dx = ax^a/x = ax^(a-1)
no matter how you do it you get the same answer!!!

2007-10-28 10:37:48 · answer #1 · answered by Anonymous · 0 0

But that's incorrect. d(x^a)/dx = ax^(a-1), not 1/x ln a. Observe:

d(x^a)/dx
d(e^(a ln x))/dx
e^(a ln x) d(a ln x)/dx
x^a d(a ln x)/dx
x^a * a/x
ax^(a-1)

2007-10-28 08:42:06 · answer #2 · answered by Pascal 7 · 0 0

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