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The formula is [Co(NH3)4(H2O)(Cl)]+
The complex is octahedral, i.e. the ligands are placed at the six points of a regular octahedron. Think of this as four in a square around the cobalt(II), one above the plane and one below.
If the four NH3 ligands are in the square and the H2O and Cl ligands are above and below, this is the trans-isomer.
If three NH3 and one of the other ligands are in the square and the other two above and below, you have the cis-isomer.
Because of the symmetry of the octahedron, these are the only possible isomers.

2007-10-28 08:22:09 · answer #1 · answered by Chemmunicator 5 · 0 0

First, you may mean cobalt(III), because cobalt(II) is labile, whereas cobalt(III) has a stiff coordination sphere.

You have to draw a "fat parallelogram" with Co in the center and lines sticking up and down from Co. The parallelogram represents a square seen edge-on and from a corner.

Start by putting all the NH3's at the corners of the square with Cl up and H2O down. That's one isomer, trans. Next, put Cl and H2O next to one another on corners of the square. Put NH3's in all the other positions. That's the second, cis.

Finally, try some more combinations to assure yourself that there are only two possibilities, with Cl and H2O either cis or trans to one another.

2007-10-28 15:20:50 · answer #2 · answered by steve_geo1 7 · 0 0

true.........false..........true --- I don't know!!!!!!!!!! What are they teaching you people in school these days? I basically just stopped by to say I'm impressed -- sorry about the stupid answer but some of these questions blow my mind and.........THIS is one of them. :)

2007-10-28 15:08:55 · answer #3 · answered by butterfliesRfree 7 · 0 0

You spelled it wrong! Google it (spelled correctly) and you will find your answer...

2007-10-28 15:15:08 · answer #4 · answered by Anonymous · 0 0

i ain't doin your homework, (that and i don't know) XD

2007-10-28 15:07:40 · answer #5 · answered by purple_platypus 1 · 0 0

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