Y+(1/3)=2
-1/3 from both sides
Y=1and 2/3s
or if what you see is (Y+1)/3=2 than you
times by 3 on both sides
Y+1=6
minus 1
y=5
it depends where the parentheses are
2007-10-28 07:57:41
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answer #1
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answered by Anonymous
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y+1/3=2
y+1=2*3
y+1=6
y=6-1
y=5
Check this by substituting the value of Y into the equation. So:
y+1/3=2
(5+1)/3=2
6/3=2 ----> Which is correct!
2007-10-28 14:59:59
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answer #2
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answered by uzi513 1
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Ans, (y+1)/3=2
y+1=6
y= 6-1=5
y=5.
2007-10-28 15:00:21
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answer #3
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answered by Sasi Kumar 4
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y+1/3=2
y+1= 6
y=5
2007-10-28 14:57:45
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answer #4
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answered by qwertx722 2
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y+1/3 = 2
````x3```x3
y+1 = 6
``` -1` -1
y = 5
2007-10-28 14:54:51
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answer #5
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answered by Sabrina 2
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You need parenthesis. (Y+1)/3 is completly different then Y+(1/3) it could be either, 3 or 5. Look at the question to determine if any parenthesis are there.
2007-10-28 14:58:16
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answer #6
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answered by heartpro101 1
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(y + 1) / 3 = 2
y + 1 = 6
y = 5
2007-11-02 13:03:53
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answer #7
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answered by Como 7
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y=5
y+1=6
6/3= 2
Now leave me alone.....my head hurts!
2007-10-28 15:01:13
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answer #8
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answered by Bunts 6
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