Hi,
Think for a moment about numbers that would be multiplied by 3.
3x1=3
3x2=6
3x3=9
3x4=12
As you can tell, all of these numbers <3,6,9,12,etc.> would be divisible by 3 because they are simply multiples of that one number!
I hope that helps you out! Please let me know if you have any other questions!
Sincerely,
Andrew
2007-10-28 07:40:58
·
answer #1
·
answered by The VC 06 7
·
0⤊
0⤋
The numbers that are divisible by 3 have a distinct property in that their digits when added together, are divisible by 3. This is a divisibility rule for 3 alone. There are similar rule (tricks) for a couple of prime numbers like 2, 5, 7, etc.
2007-10-28 07:32:17
·
answer #2
·
answered by notnot 1
·
0⤊
1⤋
the numbers whose digits added together are divisible by 3.
ex : 36 ( 3+6 = 9 divisible by 3)
72 ( 7+2 = 9 divisible by 3)
93 ( 9 + 3 = 12 divisible by 3)
2007-10-28 07:27:08
·
answer #3
·
answered by 343 3
·
2⤊
1⤋
3n, where n = any real rational number
You can also tell if a number is divisible by 3 if the sum of its digits is divisible by 3.
2007-10-28 07:28:55
·
answer #4
·
answered by ironduke8159 7
·
0⤊
1⤋
Think of the times tables you had to memorize in second grade.
2007-10-28 07:27:06
·
answer #5
·
answered by DWRead 7
·
0⤊
1⤋
any odd number
2007-10-28 07:28:22
·
answer #6
·
answered by smokey 7
·
0⤊
3⤋
3,6,9,12,15,18,21,24,27,30,33,36,39,42,45,51,52,56,
hope that is good enough enough for you
2007-10-28 09:38:53
·
answer #7
·
answered by DEBBIE C 2
·
0⤊
1⤋