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What is the internal energy change for the system if 883 joules of heat flows FROM the system into the surroundings and 365 joules of work is DONE on the system by the surroundings?

my answer was this, but the system where we submit our answers tells me that it's wrong!!

delta u = q + w
= 883 + (-365)
= 518 J

isn't that correct???

2007-10-28 06:33:50 · 2 answers · asked by Curious 1 in Science & Mathematics Chemistry

2 answers

It is not correct. :

delta U = Q-W;

= -883- (-365);
= -883+365;
= -518 J

2007-10-28 21:40:25 · answer #1 · answered by sb 7 · 0 1

That is not correct.
Please pay special attention to the positive/ negative sign.
If 883 joules of heat flows FROM the system into the surroundings, the system internal energy decreases 883J. When 365 joules of work is DONE on the system by the surroundings, the system internal energy gains 365 J. Therefore, ΔE = -883+365 = -518 (J)

2007-10-28 20:28:43 · answer #2 · answered by Hahaha 7 · 0 1

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