please explain this to me, b/c i can't remember it and i don't have my book with me! thanks!
2007-10-28 06:08:23 · 3 answers · asked by Anonymous in Science & Mathematics ➔ Chemistry
If solubility of PbCl2 is 1.6 x 10^-2 mol/L, then [Pb++] = 1.6 x 10^-2, and [Cl-] = 3.2 x 10^-2.
Ksp = [Pb++][Cl-]^2
Ksp = (1.6x10^-2)(3.2x10^-2)^2
Ksp = (1.6x10^-2)(10.2x10^-4)
Ksp = 1.6 x 10^-5
2007-10-28 06:17:59 · answer #1 · answered by steve_geo1 7 · 0⤊ 0⤋
indoors the salt answer of barium phosphate the, undissociated salts and dissociated salts are in equlibrium as Ba3(PO4)2 <--> 3Ba3+ + 2(PO4)2- then, Ksp = [Ba3+]^3 x [(PO4)2-]^2 if S is the solubility of the salt, then Ksp = (3S)^3 x (2S)^2 = (3x a million.4 x 10^-8)^3 x (2 x a million.4 x 10^-8)^2 = 5.8085 x 10^-38
2016-12-15 11:07:54 · answer #2 · answered by inabinet 4 · 0⤊ 0⤋
Ksp = [Pb+2][Cl-]^2
Ksp = (1.6x10^-2)(3.2x10^-2)^2
Ksp = 1.64 x 10^-5
[Pb+] = 1.60x10^-2
[Cl-] = 3.20x10^-2
2007-10-28 06:19:38 · answer #3 · answered by skipper 7 · 0⤊ 0⤋