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A bomb calorimeter has a heat capacity of 843 J/°C and contains 473 g of water. If the combustion of 0.500 mole of a hydrocarbon increases the temperature of the calorimeter from 22.73°C to 26.95°C, determine the heat evolved per mole of hydrocarbon.

A. 8.38 kJ
B. 23.8 kJ
C. 76.0 kJ
D. 95.9 kJ
E. 8380 kJ


Can someone just Explain the steps?

2007-10-28 06:02:09 · 1 answers · asked by Anonymous in Science & Mathematics Chemistry

1 answers

Heat capacity of water: 4.182 J/g°C.
The heat evolved per mole of hydrocarbon is:
2*(843 J/°C + 473 g*4.182 J/g°C)*(26.95°C - 22.73°C)
= 2.38x10^4 J
= 23.8 kJ
See my formula for explanations.

2007-10-28 19:28:06 · answer #1 · answered by Hahaha 7 · 0 0

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