2/x-1 + 3/2x-2?

Question

Perform the indicated operation:

2/x-1 + 3/2x-2

Write the answer in lowest terms.

Thanks!

Answer 1

2/(x-1) + 3/(2x-2)
= 2/(x-1) + 3/[2(x-1)]
= (4 + 3)/[2(x-1)]
= 7/[2(x-1)]

Answer 2

1/2

Answer 3

Find the Lowest Common Denominator

In this case, it's 2x-2 - since it can be rewritten as 2(x-1)

To get the first fraction to have that denominator, multiply that fraction by 2/2

4/2(x-1 + 3/2(x-1) = 7/2(x-1). It cannot be reduced any further.

Answer 4

carry contained in the -3, multiply each and everything it truly is "hugging" with the parenthesis. good hand part: -3(2x+a million)=-3*2x+-3*a million=-6x-3 similar with both. Left hand part: 2(x-2)=2x-2*2=2x-4 so carry all of it jointly to get -6x-3=2x-4 combine like words: -6x-2x=3-4 -8x=-a million 8x=a million x=a million/8

Answer 5

2/x-1+3/2(x-1)
2(x-1) is the LCD

the answer would be 4+3=7/ 2(x-1)

Answer 6

2/x-1 + 3/2x-2
=4x-4+3x-3/(x-1)(2x-2){.....by taking LCM}
=7x-7/(x-1)(2x-2).{by simplifying the numerator}
you can also factorize the denominator into the ax^2+by+c form.but,leaving it like this in factors is the simplest form for this sum.anyway,i guess you got what you wanted.now,what about me?...haha!just kidding!give your ten points to whom you think deserves it.

Answer 7

---condition: x - 1 diferent of 0 -> x diferent of 1
---condition: x - 2 diferent of 0 -> x diferent of 2
---2(x - 2) + 3(x - 1) = 0
---2x - 4 + 3x - 3 = 0
---5x = 7
---x = 7 / 5.

Answer 8

as in (x-1) and (2x-2) are denominators, right?

ans: 7/[2(x-1)]

u can try substituting values if u doubt my ans

Answer 9

it is.