Can someone plz help me witht these algrebra quetions plzzzzzzzzzz?

Question

I don't get this math pre-algebra crap can someone help me?
Okay so i used to get this and then we had this horrible sub that got me all confused i dont no wat im doing anymore lol i get things fast but i have to get it 100% any ways the questions are to simplify these expression

1. 2g + 3(g + 5)

2. -3z + 8(z + y)

3. 4m + 3d - 5m + d

4. t - 3 + 2(t + 2)

5. 8z + 8y + 3z

6. t - 3t + 2t + 4

7. 18 + 6(9k - 13)

8. r + 3 - 6r + r

9. -4(a + 3) - a

10. 4m + 3 - 5m + m

11. 3(g + 5) + 2g

12. 2b - 6 + 3b - b

13. -5 + 3x + 3 + 2

14. 4(w + 2x) + 9(-4w)

15. 3(2n +4) - 2(3n + 6)

16. 4a - 3 + 5a

17. 2r - 5 + 6r

Answer 1

You can do every single one of these problems by following 2 simple steps:

1.) DISTRIBUTE - if everything in a set of parentheses is being multiplied by a number, you can "distribute" that number to every term in the parentheses.

For example, if you have 2(x + 2), that's the same as
2(x) + 2(2). See? Or if you has 4(x + y - z), that's the same as 4x + 4y - 4z. You keep the same addition and subtraction signs.

2.) COMBINE LIKE TERMS - Add or subtract all like terms. In other words, add or subtract all numbers and all terms that have the same variable.

For example, if you have 4x + 3y - 2x + y, you would combine the "x's" and the "y's." 4x - 2x + 3y + y (I rearranged it) =
2x + 4y.

***A TERM is defined as any numbers or variables that are separated by addition or subtraction signs.

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I'll show you with the first few:

1.) 2g + 3(g + 5)
2g + 3g + 15 (distribute the 3)
5g + 15 (combine like terms - the "g's")

2.) -3z + 8(z + y)
-3z + 8z + 8y (distributed the 8)
5z + 8y (combined like terms - the "z's")

3.) 4m + 3d - 5m + d
-1m + 3d + d (combined like terms - the "m's")
-1m + 4d (combined like terms - the "d's")

4.) t - 3 + 2(t + 2)
t - 3 + 2t + 4 (distributed the 2)
3t - 3 + 4 (combined like terms - the "t's")
3t + 1 (combined like terms - the numbers)

5.) 8z + 8y + 3z
11z + 8y (combined like terms - the "z's")

Answer 2

The general method would be to start with the parentheses and distribute the constant through. For example:

2g + 3(g + 5)

This becomes:
2g + 3g + 15

Once all the parentheses are gone, you combine the like terms (same letters, or no letters together).
(2g + 3g) + 15

When you add the like terms, you just add the "coefficient" (the numbers in front). So 2g + 3g = 5g
5g + 15

Here's another example (#15)

3(2n + 4) - 2(3n + 6)

Distribute the 3 through:
6n + 12 - 2(3n + 6)

Do the same with the 2:
(6n + 12) - (6n + 12)

This becomes:
(6n - 6n) + (12 - 12)

This simplifies to 0 + 0 or just 0.
0

Now you try the rest on your own because you'll only understand this if you practice.

Answer 3

I can give you the answers, but it is obvious that you either do not want to do hard work or you really need help. Either ask for help or start working hard. I can give you the answerer's and you will get an f on all future tests. I can give you some hints and you can master this and get an a on future tests.

Keep this in mind;

a(g+h) = ag+ha

5a+4a=9a

5a+4 can not be added together.

Answer 4

this is pretty boring

1) 5g + 15
2) 5z+8y
3) -m+4d

and i'm very bored

Answer 5

4.3t+1
5.11z+8y
6.4
7.54k-60
8.-4r+3
9.-5a-12