A 50.0 ml sample of a 1.00 M solution of CuSo4 is mixed with 50.0 ml of 2.00 M KOH in a calorimeter. the temp

Question

erature of both solution was 20.2 degree C before mixing and 26.3 degree C after mixing. the heat capacity of the calorimeter is 12.1 J/k. from these data calculate delta H for the process.
CuSo4(1M) + 2KOH(2M) to form Cu(OH)2(s) + K2So4(0.5 M)

Answer 1

elevation of temperature is 26.3-6.1=6.2°C
You need for this Q=mcdt for 100ml=1g of water heat capacity of water =4.184J/k
so q= 100*4.184*6.2 =2594J and you add 12.1*6=72.6 j

Q=2666.7J for this reaction
this for 0.1M
so for 1 mole 26667J/mole