end to reach the speed of light?
degrees= 360
time= 1 sec
length= ?
*no air resistance or gravity
2007-10-28 02:42:33 · 6 answers · asked by tat6504 2 in Science & Mathematics ➔ Physics
I will use 300,000 km/h as the speed of light.
First we need to find out how many km light travels in a second:
300,000 ÷ 3600 (number of seconds in an hour) = 83.3 km/s
Then we divide by pi to find the length of the pole.
83 ÷ pi = 26.5 km.
So the length of the pole is 26.5 km
2007-10-28 02:51:25 · answer #1 · answered by jlao04 3 · 0⤊ 0⤋
Well...for a circle, the velocity is defined as (2*pi*r)/t...set the velocity equal to the speed of light, solve for r, and then muptiply that by 2 to get the length of the pole.
2007-10-28 09:47:30 · answer #2 · answered by cdash77 1 · 0⤊ 0⤋
theorectically speaking, to move at light speed, the pole would need to be at about 4.78 x 10^7 metres. however, according to einstein's theory of relativity, it is impossible for an object with mass to reach light speed.
by the way, i used light speed as 3 x 10^8 metres per second
2007-10-28 09:59:10 · answer #3 · answered by maximus 1 · 0⤊ 0⤋
Wow. What are they teaching in school now. It does not matter how "long", the length, the pole is it still rotates at the same speed. 60 rpm.
2007-10-28 10:25:39 · answer #4 · answered by gdc 3 · 0⤊ 0⤋
Ill look it up 4 u
2007-10-28 09:51:36 · answer #5 · answered by Miley C 1 · 0⤊ 0⤋
v = w R
3x10^8m/s = 2(pi) R
R = [(3x10^8)/ 2(pi)]
R = 47746523 m
2007-10-28 10:18:53 · answer #6 · answered by rene c 4 · 0⤊ 0⤋