Find values of a and b so that the function r has a local minimum at (8,16)
Find the vertical asymptotes of r based on these values
2007-10-26 21:02:40 · 2 answers · asked by wildcat11 1 in Science & Mathematics ➔ Mathematics
The derivative is f´(x) = 1/[a-(x-b)^2]^2 *2((x-b) must be zero at x=8 so b=8
f(8)= 16 = 1/(a) so a = 1/16 and f(x)= 1/[1/16 -(x-8)^2]
A vertical asymptote occurs when the denominator is 0
so
1/16 =( x-8)^2 and x=8+-1/4
so x= 33/4 and x= 31/4 are the asymptotes(verticals)
2007-10-27 02:16:36 · answer #1 · answered by santmann2002 7 · 0⤊ 0⤋
try this website mathworld.wolfram.com it's the best math site out there it even has animations in some cases to explain the concept. (Sorry I'm a math teacher so I can't really just give you the answer.) Hope it helps
2007-10-26 21:08:43 · answer #2 · answered by Rebecca R 3 · 0⤊ 0⤋