f(x0 = 2 - X2 adn g(x) = 2x^3 - 5
solve:
(f +g)(2)
(f-g)(-3)
(FG)(-2)
(f/g)(4)
I am SOO LOST
2007-10-26 14:31:35 · 4 answers · asked by a a 1 in Science & Mathematics ➔ Mathematics
use the f(x) and g(x) to substitute for the problems you need to solve.
ex. [(2-x^2)+(2x^3-5)](2)=0
solve for x
2007-10-26 14:38:39 · answer #1 · answered by pAgnAliA 4 · 0⤊ 0⤋
(f +g)(2) = f(x) + g(x) = (2-2^2) + (2*2^3-5) = -2 + 11 = 9
(f-g)(-3) = f(-3) - g(-3)
(fg)(-2) = f(-2)g(-2)
(f/g)(4) = f(4)/g(4)
2007-10-26 21:37:39 · answer #2 · answered by sahsjing 7 · 0⤊ 1⤋
1) 2f+2g
2)-3f+3g
3)-2F-2G
4)4f+4g
too slve it i used distributive property. but im only in algabra 1 and so it might be incorrect.
2007-10-26 21:38:37 · answer #3 · answered by jess_here2 4 · 0⤊ 1⤋
(f + g)(x) = f(x) + g(x)
(f - g)(x) = f(x) - g(x)
(fg)(x) = f(x)g(x)
(f/g)(x) = f(x)/g(x)
Does that help any?
2007-10-26 21:37:31 · answer #4 · answered by Demiurge42 7 · 0⤊ 1⤋