2007-10-26 14:05:05 · 9 answers · asked by Nicole D 1 in Science & Mathematics ➔ Mathematics
[18]
5x^2-45x+70
=5(x^2-9x+14)
=5(x^2-2x-7x+14)
=5{x(x-2)-7(x-2)}
=5(x-2)(x-7)
2007-10-26 14:10:28 · answer #1 · answered by alpha 7 · 0⤊ 0⤋
Always look for a greatest common factor among all the terms. Here, all three terms are multiples of 5. Factor it out:
5x² - 45x + 70 = 5(x² - 9x + 14).
Next, see if you can "unfoil" the trinomial. Here, you're looking for two numbers that mulitply to (+14) that also add to (-9). If you think about it, you should be able to find (-7) and (-2) would do the trick.
Fully factored,
5x² - 45x + 70
= 5(x² - 9x + 14)
= 5(x - 7)(x - 2).
2007-10-26 14:11:22 · answer #2 · answered by Anonymous · 0⤊ 0⤋
5x^2 - 45x + 70
= 5(x^2 - 9 + 14)
= 5(x - 7)(x - 2)
2007-10-26 14:11:01 · answer #3 · answered by balletdancerbrad 1 · 0⤊ 0⤋
5x² - 45x + 70
5 (x² - 9x + 14)
5 (x - 2)(x - 7)
2007-10-26 14:14:39 · answer #4 · answered by The Glorious S.O.B. 7 · 0⤊ 0⤋
5 is a common factor of all the numbers so factor a 5 out and your equation now looks like this
5(x^2 - 9x + 14)
Factor the () now
5(x-7)(x-2)
This is the complete factorization of this problem.
2007-10-26 14:08:18 · answer #5 · answered by Ms. Exxclusive 5 · 0⤊ 0⤋
5 ( x ² - 9 x + 14 )
5 ( x - 7 ) ( x - 2 )
2007-10-30 08:55:49 · answer #6 · answered by Como 7 · 0⤊ 0⤋
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2016-12-15 10:13:16 · answer #7 · answered by Anonymous · 0⤊ 0⤋
Find two numbers that multiply to 5: 1 and 5
Find two numbers that multiply to 70: 2 and 35
Arrange this into a cross
............|..............
....1......|.....-2.......
._____|______
............|..............
....5......|......-35....
Make sure when you multiply the diagonals they add up to (-45) and your answers are horizontal coefficients:
(x - 2)(5x - 35)
2007-10-26 14:11:03 · answer #8 · answered by Filip J 1 · 0⤊ 0⤋
5x^2-45x+70
5(x^2-9x+14)
5(x^2-2x-7x+14)
5{x(x-2)-7(x-2)}
=5(x-2)(x-7)
2007-10-26 14:58:14 · answer #9 · answered by UNIQUE 3 · 0⤊ 0⤋