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2007-10-26 14:03:46 · 8 answers · asked by Anonymous in Science & Mathematics Mathematics

8 answers

24 - 18x + 4x < 27 + 6x
24 - 14x < 27 + 6x
- 3 < 20x
x > - 3 / 20

2007-10-30 08:48:54 · answer #1 · answered by Como 7 · 1 0

Remove parentheses and rearrange terms to isolate x:
6(4-3x)+4x<3(9+2x)
⇒ 24 - 18x + 4x < 27 + 6x
⇒ -20x < 3
⇒ x > -3/20

2007-10-26 14:14:11 · answer #2 · answered by DWRead 7 · 0 0

6 (4 - 3x) + 4x < 3 (9 + 2x)
24 - 18x + 4x < 27 + 6x
24 - 14x < 27 + 6x
-3 - 14x < 6x
-3 < 20x
-3/20 < x

Negative three twentieths are less then x.

2007-10-26 14:13:27 · answer #3 · answered by The Glorious S.O.B. 7 · 0 0

First you do the left side of the inequality (an equation with < or >) first. You distribute the 6 with the 4-3x. 6 times 4 is 24 and 6 times -3x is -18x. Then you add the -18x with the 4x that is already there and you get -14x. So the left side of the equation should look like this:
24-14x
Now you do the right side. First you distribute the 3 with 9+2x. 3 times 9 is 27 and 3 times 2x is 6x. So your right side should look like this:
27+6x
Now you put the both sides together to get this:
24-14x<27+6x
However, you're not done. Now you add 14x to both sides of the equation to bring 20x to one side. Like this:
24-14x<27+6x
+14x +14x
24<27+20x
Now you subtract 27 from both sides to get the 20x alone by itself. Like this:
24<27+20x
-27 -27
-3<20x
Now that you got 20x to one side, you have to get the x alone by itself. You divide each side by 20 to get rid of the 20 from 20x. Like this:
-3 < 20x
/20 /20
-3/20 That is the answer but you should switch it around to make it look better like this:
-3/20 x>-3/20

2007-10-26 14:22:52 · answer #4 · answered by dj_azn 2 · 0 1

6(4-3x)+4x < 3(9+2x)
24-18x+4x < 27 + 6x
24-14x < 27 + 6x
-14x-6x<27-24
-20x < 3
x < 0.15

2007-10-26 17:47:01 · answer #5 · answered by Kenneth Koh 5 · 0 1

All you do is do away with the brackets and simplify the equation: sixty 4 = 3x - 11 + 2x -2 sixty 4 = 3x +2x - 11 - 2 sixty 4 = 5x - 13 Now, rearrange the equation so which you have coefficients on one area (something that purely has a selection) and variables on the different (x is a variable). yet in a distinctive way of observing it rather is to characteristic 13 to the two aspects of the equation so which you will do away with the -13 on the stunning area. sixty 4 + 13 = 5x - 13 + 13 seventy seven = 5x x = seventy seven/5

2016-10-02 21:31:19 · answer #6 · answered by harren 4 · 0 0

x<1/12

6(4-3x)+4 = 28-18x
3(9+2x) = 27+6x
28-18x<27+6x
+18x +18x
28<27+24x
-27 -27
1<24x
_ _
24 24
1/241/24

2007-10-26 14:12:09 · answer #7 · answered by Anonymous · 0 0

6(4-3x)+4x<3(9+2x)
24-18x+4x<27+6x
-14x<3+6x
-20x<3
x>-3/20

2007-10-26 14:10:11 · answer #8 · answered by J D 5 · 0 0

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