How do i find the 2 dinates of where the line crosses the y-axis for this equation?

Question

3x+2y-8=0

Can someone please explain how you do it??

Answer 1

The y-axis has equation x=0. So 0 is the x-coordinate of the point you're looking for. To get the y-coordinate, set x=0 in your equation and solve for y.

Answer 2

What is true about any point on the x-axis???? Hmmmm, its y-coordinate is zero! The points (-5,0), (-2,0), (0,0),(4,0),
(57,0), etc., are all on the x-axis since y-coordinates are zero on the x-AXIS.

And all points on the y-axis have x-coordinates of zero.

So when you want to find the point on the y-axis where the line crosses it, you substitute 0 for x and solve for y.

If you want to thind the point on the x-axis where the line crosses it, you substitute 0 for y in your equation and solve for x.

So for the point where the line crosses the x-axis we let y=0

3x + 2(0) - 8 = 0 so 3x = -8 and x = -8/3

So the point where line crosses x-axis is (-8/3, 0).

Now you should be able to find the point where the line crosses the y-axis.

Answer 3

when a line crosses y axis so x=0
so put x=0 to get y
3 * 0 + 2y -8 =0
y= 5/2 =2.5
so the point is (0, 2.5)