An archer pulls her bowstring back 0.420 m by exerting a force that increases uniformly from zero to 222 N.
(a) What is the equivalent spring constant of the bow?
(b) How much work does the archer do in pulling the bow?
2007-10-26 11:02:28 · 3 answers · asked by bob 1 in Science & Mathematics ➔ Physics
a) Spring constant is force per distance. so it's given that at .420m the force is 222N, and the spring constant is 222/.42 N/m.
b) work is force times distance. the force increases linearly so you can assume work = the average force times distance, or = 222/2 * .42 Nm
2007-10-26 12:15:24 · answer #1 · answered by Piglet O 6 · 4⤊ 0⤋
to clarify, The above comment is incorrect don't waste one of your tries on doing it with ( ....). do not use them .
2017-02-26 21:56:38 · answer #2 · answered by Jordan 1 · 0⤊ 0⤋
To clarify the answer above for b) its = (222/2)*.42 Nm
2016-02-24 21:17:07 · answer #3 · answered by Peter 1 · 0⤊ 1⤋