find the differential dy?

0 ⤊

find the differential dy?

y=(x^2)/(3x-1)

please show as much work as possible im pretty sure i did it wrong

2007-10-26 08:48:00 · 4 answers · asked by dee j 1 in Science & Mathematics ➔ Mathematics

4 answers

y=(x^2)/(3x-1)
=> dy/dx = [(3x-1)(2x) -(x^2)(3)]/ (3x-1)^2

2007-10-26 08:53:26 · answer #1 · answered by harry m 6 · 0⤊ 0⤋

y' = {(3x-1) (2x) - (x^2) (3)} / (3x-1)^2 by quotient rule
y' = {3x^2 - 2x} / (3x-1)^2 distribute the 2x and 3 in numer.
y' = {x(3x-2)} / (3x-1)^2 factor out an x in the numerator

2007-10-26 15:59:22 · answer #2 · answered by Anonymous · 0⤊ 0⤋

The differential dy is defined to be dy = (dy/dx)*dx.

2007-10-26 16:00:27 · answer #3 · answered by Tony 7 · 0⤊ 0⤋

dx/dy= [(-3x^2) / (3x-1)^2] +[(2x / 3x-1)]

2007-10-26 15:56:50 · answer #4 · answered by vmaldonado111 1 · 0⤊ 1⤋