2007-10-26 07:37:07 · 9 answers · asked by yanksrule4691 1 in Science & Mathematics ➔ Mathematics
3x + 6 ≤ 2
3x ≤ - 4
x ≤ - 4 / 3
2007-10-28 07:38:11 · answer #1 · answered by Como 7 · 0⤊ 0⤋
(-infinity, -4/3] you have to get x by itself b-4 you can realy do anything else
2007-10-26 07:43:24
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answer #2
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answered by bieta_102 1
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0⤊
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3x+6
3x< or equal to -4
/3 /3
x
3x + 6 <= 2
3x <= -4 {subtract 6 from both sides}
x <= -4/3 {divide both sides by 3}
2007-10-26 07:40:49 · answer #3 · answered by Anonymous · 0⤊ 0⤋
(3x+6)
3x,or equal to -4
/3 /3
x= -1 1/3
x= -1.33
2007-10-26 07:49:42 · answer #4 · answered by smileslots59 1 · 0⤊ 0⤋
(3x+6)< or equal to 2
3x <= -4
x <= -4/3
(- infinity, -4/3]
2007-10-26 07:41:37 · answer #5 · answered by ironduke8159 7 · 0⤊ 0⤋
3x+6≤2
=3x≤-4
=x≤ -4/3
Solution = x≤ -4/3
2007-10-26 07:41:36 · answer #6 · answered by Anonymous · 0⤊ 0⤋
Sahsjing is right, but i'll give you the process of the answer:
3x+6 < 2
3x < 2- 6
3x < -4
x < (-4/3)
I hope i could help you,
[♥Susanita♥]
2007-10-26 07:48:33 · answer #7 · answered by Anonymous · 1⤊ 0⤋
3x+6≤2
3x≤-4
x≤ -4/3
2007-10-26 07:39:50 · answer #8 · answered by chasrmck 6 · 1⤊ 0⤋
x ≤ -4/3
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Ideas: Move 6 to the right side, and then divide both sides by 3.
2007-10-26 07:39:26 · answer #9 · answered by sahsjing 7 · 1⤊ 0⤋