Given the function g(x)=3x-3 with a domain of {x/-2< or equal to x < or equal to 4}find the range?

Answer 1

Hi,
g(-2) = 3(-2) -3
= -6-3
=-9
g(4) = 3(4) -3
=12-3
=9
Range is [-9,9]

FE

Answer 2

g(x) = 3x – 3

With the domain of [–2, 4], substitute these values in for the function. Since g(x) is strictly increasing, the range is simply [g(–2), g(4)] = [–9, 9]. That is, the domain {x | –2 ≤ x ≤ 4} corresponds to the range {g(x) | –9 ≤ g(x) ≤ 9}.