sinq/cosq + cosq/sinq
2007-10-26 07:29:47 · 3 answers · asked by Hamid K 1 in Science & Mathematics ➔ Mathematics
Step by step this is how you do it.
sinq/cosq + cosq/sinq
sin²q/(sinqcosq) + cos²q/(sinqcosq)
(sin²q + cos²q)/(sinqcosq)
1/(sinqcosq)
2/(2sinqcosq)
2/sin2q
½csc2q
So
sinq/cosq+cosq/sinq = ½csc2q
2007-10-26 07:38:33 · answer #1 · answered by Astral Walker 7 · 1⤊ 1⤋
Step by step this is how you do it.
sinq/cosq + cosq/sinq
sin²q/(sinqcosq) + cos²q/(sinqcosq)
(sin²q + cos²q)/(sinqcosq)
1/(sinqcosq)
2/(2sinqcosq)
2/sin2q
½csc2q
So
sinq/cosq+cosq/sinq = ½csc2q
2007-10-27 03:16:45 · answer #2 · answered by stuartelliott797 2 · 0⤊ 1⤋
( sin ² q + cos ² q ) / (sin q cos q)
1 / (sin q cos q)
2 / (2 sin q cos q)
2 / sin 2q
2 cosec 2q
2007-10-30 05:52:30 · answer #3 · answered by Como 7 · 1⤊ 0⤋