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2 answers

Sums of angels in a triangle
A+B+C=180
A=180-( B+C)= 180 -141=39 deg

Sinus sentence tells us:
a/sinA=b/sinB
a=(b/sinB) x sinA=( 35 /sin 29) x sin 39= 45.5

c=(b/sinb) x sinC= (35/sin 29) x sin 112= 66.5

2007-10-26 08:02:59 · answer #1 · answered by anordtug 6 · 0 0

sine rule
a/SIN A = b/SIN B = c/SIN C
b/SIN B = c/SIN C
35/SIN 29 = c/SIN 112
c= (35/SIN 29)/SIN 112

2007-10-27 10:21:46 · answer #2 · answered by stuartelliott797 2 · 0 0

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