Graph the line and label the x- and y- intercepts.
-3x/4 + y/2 = 0
2007-10-26 07:07:50 · 5 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
y/2=3x/4
y=6x/4
The intercepts are at (0,0)
The slope is +1.5
2007-10-26 07:17:44 · answer #1 · answered by frozen 5 · 0⤊ 0⤋
-3x/4 + y/2 = 0
y=3x/2
when x-0, y=0
when y=0, x=0
or compare to y=mx+c
intercept is not present so the line goes thru' 0,0
and the slope is 1.5
2007-10-26 07:35:39 · answer #2 · answered by Anonymous · 0⤊ 0⤋
rearrange the eq
-3x +2y = 0
2y = 3x
y = 3/2 * x
this is a straight line through the origin.
x intercept is when y = 0 and
y intercept is when x = 0
so in this case both = 0
2007-10-26 07:15:54 · answer #3 · answered by norman 7 · 0⤊ 2⤋
---For x = 0 then -> y = 0
--- -3x/4 = -y/2
--- 3x/4 = y/2 -> 6x = 4y -> y = 3x/2.
---For every y = 3x/2.
2007-10-26 07:17:19 · answer #4 · answered by Anonymous · 0⤊ 1⤋
y=3/2x+0
p.s. ur hot
2007-10-26 07:17:11 · answer #5 · answered by kyle f 2 · 0⤊ 1⤋