2007-10-26 05:44:11 · 6 answers · asked by pdick06 1 in Science & Mathematics ➔ Mathematics
( x ² - 3x + 2 ) / (x + 1) = x - 4 + 6 / (x + 1)
I = ∫ x - 4 + 6 / (x + 1) dx
I = x ² / 2 - 4 x + 6 log (x + 1) + C
2007-10-30 05:33:04 · answer #1 · answered by Como 7 · 0⤊ 0⤋
integral of x2-3x+2/x+1 dx is:
= (x^3)/3 - 3 (x^2)/2 + 2 lnx + x + c << answer.
c arbitrary constant.
2007-10-26 05:48:51 · answer #2 · answered by Shh! Be vewy, vewy quiet 6 · 0⤊ 0⤋
I don't know if your last denominator is x or x+1.
Anyway, just integrate term by term.
Assuming your denominator is x, you get
x³/3 - 3x²/2 + 2 ln|x| + x + C.
If the last denominator is x+1,
you get
x³/3 - 3x²/2 + 2 ln|x +1| + C.
2007-10-26 05:51:26 · answer #3 · answered by steiner1745 7 · 0⤊ 0⤋
3x^5 / x^3 => 3x^2 3x^2 * (x^3 + a million) = 3x^5 + 3x^2 3x^5 - 2x^3 + 5x^2 - 3x^5 - 3x^2 = -2x^3 + 3x^2 -2x^3 / x^3 = -2 -2 * (x^3 + a million) = -2x^3 - 2 -2x^3 + 3x^2 - 2 + 2x^3 + 2 = 3x^2 3x^2 - 2 + 3x^2 / (x^3 + a million) u = a million + x^3 du = 3x^2 * dx 3x^2 * dx - 2 * dx + 3x^2 * dx / (a million + x^3) => 3x^2 * dx - 2 * dx + du / u combine x^3 - 2x + ln|u| + C => x^3 - 2x + ln|a million + x^3| + C
2016-10-14 02:48:44 · answer #4 · answered by mcclune 4 · 0⤊ 0⤋
Well, apparently YOU find it by posting it here as a question....
2007-10-26 05:54:44 · answer #5 · answered by Azure Z 6 · 0⤊ 0⤋
its d
2007-10-26 05:46:33 · answer #6 · answered by tom p 6 · 0⤊ 2⤋