what does a graph of sin^2 x look like? similar to sin x ? thanks!?

Answer 1

Cannot draw this here unfortunately.
The thing to note is that if y = sin ² x, y is always positive.

The graph of of sin ² x is obtained from the graph of sin x by reflecting in the x axis, the parts of y = sin x that lie below the x axis.

By so doing, a graph is obtained that is always positive for y.

A series of "humps" but this is hardly a Mathematical expression!
"Humps" repeat every 180°

Answer 2

Draws the graph of sin(x)

Then take all the portions of the graph that are negative and flip them about the x axis to get a graph that looks a little like a bouncing ball. Its maximum is still 1 but all other values of y must be replaced with their squares so 1/2 on y=sinx becomes 1/4 on y = sin^2x.

Answer 3

sin^2 x = (-1/2)cos2x + 1/2
Therefore, the graph of sin^2 x is similar to the graph of (1/2)cos2x. If you flip (1/2)cos2x over the x-axis and move it up by 1/2, then you get the graph of sin^2 x.

Answer 4

Graph Of Sin 2x

Answer 5

sin^2 x is another way of writing (sin x)^2.

Think about the values of sin:

sin 0 = 0, so (sin 0)^2 = 0
sin 30 degrees = sqrt(2)/2, so that squared would be 1/2
sin 60 degrees = sqrt(3)/2, so that squared would be 3/4
sin 90 degrees = 1, that squared is 1.

And so forth.

Remember, of course, that squaring makes the negatives go away -- IE: sin 270 degrees = -1, that squared is positive 1.

So it doesn't look exactly like sin x.

Answer 6

no the graph of sin x alternates in the positive and negative regions of the y axis right?
for sin^2 x all the parts of the graph which are below the x axis get inverted upwards ( like a mirror image about x axis) so that everything is above the x axis..so the period of the function becomes pi instead od 2pi because it seems to be repeating after every pi

Answer 7

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what does a graph of sin^2 x look like? similar to sin x ? thanks!?

Answer 8

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y = sin(2(x - pi)) = sin(2x - 2pi) = sin(2x) Note that we can remove the -2pi, as the sine function repeats itself every 2pi. Putting it simply, we obtain y = sin2(x - pi) by shifting y = sin(2x) to the right by 2pi units. However, this shifting does not cause any major changes, as the y-value will still be the same for each x-value (due to the period of sine functions being 2pi). Hence, y = sin(2(x - pi)) is the same as y = sin(2x)

Answer 9

sin2(x)+sin(x)=0 2sinxcosx+sinx=0 sinx(2cosx+1)=0 answer is sinx=0;x=0; and cosx=minus 1/2;x=120 degrees