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what is its average angular speed in rad/s?
if two people were on it one at 4.0 m and one at 5.0 m from the center, what would there their tangential speeds?

2007-10-26 04:36:15 · 2 answers · asked by Pascal 4 in Science & Mathematics Physics

2 answers

1 rev = 2*pi radians so

angular speed w =#radians/time = 2*pi*24/(3*60) = pi/90 = 0.035 rad/s

tangential speed v = w*r

v(4m) = 0.035*4 = 0.14 m/s

v(5m) = 0.17 m/s

2007-10-26 04:44:47 · answer #1 · answered by nyphdinmd 7 · 0 0

one revolution corresponds to 2pi radians so 24 rev correspond to 48pi radians which is done in 3 min . 3 min is 180sec --so its angulare speed is 48pi divided by 180 which is (4pi / 15) radians per sec . the tangential speeds are (4
times 4pi / 15) m/s and (5 times 4pi over 15 m/sec). which come to 16pi/15 m / s and 4/3pi m per sec

2007-10-26 11:49:40 · answer #2 · answered by Anonymous · 0 0

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