Could someone please explain how I would evaluate this problem without a calculator?: (Sin 60°)² + (Cos 60°)²

Answer 1

[07]
sin^2 +cos^2 of any angle is always 1
The answer,therefore,is 1.

Answer 2

sin 60° = √3 / 2
cos 60° = 1 / 2
sin ² 60° + cos ² 60° = 3 / 4 + 1 / 4
sin ² 60° + cos ² 60° = 1

Answer 3

Sin(60) = (sqrt3)/2.

squaring this you have 3/4

Cos(60) = 1/2

square this you have 1/4




3/4 + 1/4 = 1

I would suggest getting the sin, cos, and tan of the more common angles put to memory. Know 0, 30, 45, 60, 90. You can also use the unit circle and law of sines to figure them out. Remember the hypotenuse is always 1 on the unit circle.

Right! Remember your trig identities, I forgot to mention that!

Answer 4

You would use the trignometric relationship that (sin(any angle))^2 + (cos(any angle))^2 = 1.

In this case (sin 60)^2 + (cos 60)^2 = 1

Checking that answer using a calculator yeilds:
(sin 60)^2 = 0.75
(cos 60)^2 = 0.25
(sin 60)^2 + (cos 60)^2 = 0.75 + 0.25 = 1

Answer 5

From Trigo Identity, sin^2 (x) + cos^2 (x) = 1,
where x is arbitrary angle.

Alternative, you can replace
sin 60 = 1/2[Sqrt(3)]
cos 60 = 1/2

Answer 6

Sin 60° = √3/2
and
Cos 60° = 1/2

so
(Sin 60°)² + (Cos 60°)²
= (√3/2)² + (1/2)²
= (√3)²/2² + 1²/2²
= 3/4 + 1/4
= 1

,.,.,.,.,.,.,.,..,.

Answer 7

(Sin 60)^2 + (Cos 60)^2
= (Surd 3/2)^2 + (1/2)^2
= 3/4 + 1/4
= 1

Answer 8

The point of this problem is that you use trigonometric identities. As the other answers indicate,
(Sin x°)² + (Cos x°)² =1

This holds true no matter what value you use for your angle, as long as both Sine's angle and Cosine's angle are the same.

Answer 9

It is a standard trigonometric equation dude
Sin^2 Q + Cos^2 Q = 1
Q can be any angle
so ur answer is 1.

Answer 10

sin(A)^2 + cos(A)^2 = 1
The answer is one.