cos(t)=sqrt2/2 and cos(t)= -sqrt2/2?

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Solve the following equations in terms of pi in the interval [0,2pi].

2007-10-26 03:25:49 · 2 answers · asked by Ciavana 3 in Science & Mathematics ➔ Mathematics

cos t = √2 / 2
t = π/4 , 7π/4

cos t = - √2 / 2
t = 3π/4 , 5π/4

2007-10-29 23:24:12 · answer #1 · answered by Como 7 · 0⤊ 0⤋

As sqrt(2) / 2 is sin(pi/4), the solutions of the first equation are:
t = pi/4, 7pi/4,

and those of the second equation are:
t = 3pi/4, 5pi/4.

2007-10-26 10:49:39 · answer #2 · answered by Anonymous · 0⤊ 0⤋