2007-10-26 02:57:32 · 3 answers · asked by ralph 1 in Science & Mathematics ➔ Physics
This a general equation for motion under constant acceleration
S=S0 + V0t + 0.5gt^2
S0 - initial position
V0 - initial velocity
g - acceleration due to gravity (hopefully constant)
t - time in flight
Downward
Since it is a free fall V0=0 and if we consider the point we drop to be the starting point in space S0=0 we have
S=0.5gt^2
Upward
If we throw something upward V0 has a value
S=V0t - 0.5gt^2 (notice how I sneaked a minus sign in)
at the very top S=0
Also keep in mind time up equals to time down if there is no air resistance.
Does that help?
2007-10-26 03:10:31 · answer #1 · answered by Edward 7 · 0⤊ 0⤋
The formula for the free fall is:
Vy = g*t
Y = 1/2*g*t^2
The formula for an object thrown directly upward is:
Vy = v0y-gt
Y= v0y*t-1/2*g*t^2
2007-10-26 10:17:57 · answer #2 · answered by lonelyspirit 5 · 0⤊ 0⤋
S=v0*t+0.5*g*t^2
directly downward:v0=0
directly upward :v0=-v ,v is the initial speed(v>0)
2007-10-26 10:16:18 · answer #3 · answered by Anonymous · 0⤊ 0⤋