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f is continuous on [0,4] and differentiable on (0,4). Also, suppose f(0) =1
and 3 a. 13 b. 3 c. 12 d. undefined

2007-10-26 01:25:34 · 2 answers · asked by programhelp 2 in Science & Mathematics Mathematics

2 answers

By the mean value theorem, there exists an a in (0,4) such that f(4) = f(0) +(4 -0) f'(a) = 1 + 4 f'(a). Since 3
1 + 4*3 < f(4) < 1 + 4*6, or
13 < f(4) < 25 (a)

2007-10-26 01:42:39 · answer #1 · answered by Steiner 7 · 0 0

b. 3

you silly sausage

2007-10-26 08:29:09 · answer #2 · answered by Anonymous · 0 1

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