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I have this:

(secx-1)tan^3 x * sec^3 x dx

let u = sec x
so du = secxtanx

Now what?

2007-10-25 17:36:21 · 2 answers · asked by officerbrother 2 in Science & Mathematics Mathematics

2 answers

Recall tan^2 x = sec^2 x - 1

Then you end up with
(u-1)*(u^2 - 1) * u^2 * du
Expand and integrate

2007-10-25 17:42:42 · answer #1 · answered by Dr D 7 · 1 0

u and du take care of everything but a factor of tan² x
For that, you can use the fact that tan² x = sec² x - 1

2007-10-25 17:45:19 · answer #2 · answered by Ron W 7 · 0 0

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