P AND (NOT Q) AND (NOT R)
keeping in mind where I say "OR" you can also say "union" or "+" (plus), and where I say "AND", you can also say "intersection" or "*" (times), depending on whether you choose to use Aristotelian, Venn, or Boolean conventions. Sometimes you also see NOT rendered as "~".
This identifies that we are looking at anything that is both P and NOT Q and NOT R. In other words, any part of P that is not included in Q or R.
DeMorgan's theorem states that any expression of the form
A OR B can also be expressed as NOT((NOT A) AND (NOT B)) or, that any expression of the form A AND B can be expressed as NOT ((NOT A) OR (NOT B)). In other words, put a single NOT on the outside, two NOTs on the inside, and change the operator from AND to OR, or OR to AND. If you get two NOT's on each other, they cancel out.
Therefore,
P AND (NOT Q) AND (NOT R)
can also be expressed as:
NOT ((NOT P) OR Q OR R))
or
P AND NOT(Q OR R)
2007-10-25 17:19:01
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answer #1
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answered by Don M 7
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Warning to answerers: Website is loaded with spyware and does not contain a Venn diagram!
2007-10-25 16:48:43
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answer #2
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answered by Hall + Oates 6
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well the shaded area is the stuff that's just in the 'p' category and nothing else.
what exactly are you asking?
2007-10-25 16:49:06
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answer #3
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answered by Pyro 6
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i dont know maybe a ven diagram
2007-10-25 16:48:59
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answer #4
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answered by tito 2
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I'm not sure what you're after, but here's a shot :
P & !Q & !R
or
P & !(Q || R)
(! = not, & = AND, || = OR)
2007-10-25 16:51:08
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answer #5
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answered by gitter1226 5
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P ∩ (Q U R)^c
2007-10-25 16:59:52
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answer #6
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answered by ǝɯɐuɹǝsn ɔıɹǝuǝƃ 3
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P\(Q∪R)
2007-10-25 16:50:22
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answer #7
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answered by Pascal 7
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P AND (NOT Q) AND (NOT R)
2007-10-25 16:49:58
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answer #8
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answered by norman 7
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