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y= sec(tanx)

2007-10-25 16:22:40 · 1 answers · asked by Anonymous in Science & Mathematics Mathematics

1 answers

let u = tan x y=sec u

du/dx = sec^2x
dy/du = sec u tan u

dy/du * du/dx = sec^2(x) sec(tanx)tan(tanx)

2007-10-25 16:30:32 · answer #1 · answered by norman 7 · 0 0

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