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2007-10-25 12:57:21 · 2 answers · asked by Jake 1 in Science & Mathematics Mathematics

2 answers

A disk? As something like a 3D coin? Okay:

z = (±a/b) ((b/2)^c - (x² + y²)^c)^(1/c)

where a is the thickness of the disc, b is the diameter of the disc, and c is some arbitrarily large number. The higher c is, the more square the edges of this disc will be, so it would be more like a coin instead of a pill.

2007-10-25 13:13:17 · answer #1 · answered by Scythian1950 7 · 0 0

Assume the 3 major axes all perpendicular to one another, x,y,z
Let t be the uniform thickness of the disk, r the radius
Let the equation of the disk be z= z(x,y) ie z is a function of x,y
z = does not exist if sqr[x^2+y^2] > |r|
z = t if sqr[x^2+y^2] <= |r|
note that the absolute value for r does not really need to be here, I just do that to remind myself that r is always >=0

2007-10-25 13:09:45 · answer #2 · answered by kellenraid 6 · 0 0

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