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2007-10-25 12:37:09 · 3 answers · asked by Shane W 1 in Science & Mathematics Mathematics

3 answers

f'(x) = 4x^3 · e^4x + 3x^2 · e^4x
f'(x) = (4x^3 + 3x^2)e^4x

2007-10-25 12:47:50 · answer #1 · answered by Helmut 7 · 0 0

product rule: 1st times the derivative of the 2nd + the 2nd times the derivative of the 1st

f'(x)= x^3 times e^4x times 4 +e^4x times 3x^2

= e^4x(4x^3 + 3x^2)

2007-10-25 19:50:56 · answer #2 · answered by Anonymous · 0 0

The derivative is 3x^2(e^4x) + 4x^3(e^4x).

2007-10-25 19:50:24 · answer #3 · answered by mr_laker2003 2 · 0 0

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