10---- Find, in radical form, the distance between the points (-3,7) and (4,2)
12--- 4x^2-9 * 4x-8 Simplify (the line thing I made is division)
______ _____
2x^2-x-6 2x+4
13---- Solve the following system of equasions graphically and check
y=x^2-8x+10
y=x-8
Is this the kind where you graph each seperatley then get the point where they cross? and i know how to graph the second one but can you put the 1st on in y=mx for or whatever you need to solve it
Thank you very very much!
2007-10-25 12:27:17 · 3 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
(-3,7) and (4,2)
= sqrt(7^2 +5^2) = sqrt(74)
(4x^2 -9)/(2x^2-x-6) * (4x-8)/(2x+4)
= (2x+3)(2x-3)/[(x-2)(2x+3) * 4(x-2)/(2(x+2))
= 2(2x-3)/(x+2)
x^2-8x+10 is a parabola with axis of symmetry x = 4.
Its vertex is at (4, -6). Its y-intercept is (0,10).
Its x-intercepts are at x = (4+/- sqrt(6), 0). That should allow you to sketch its graph. If you need to, plot a few more values of (x,y). The graph should look like a U, where the bottom of the U is the vertex of the paarabola.
The line and parabola will intersect when x^2-8x+10 = x-8
So x^2-9x +18 = 0
(x-6)(x-3) = 0
x = 6 and x = 3
Line intersects parabola at (3, -5) and (6, -2)
2007-10-25 13:00:05 · answer #1 · answered by ironduke8159 7 · 0⤊ 0⤋
i dont know but its y=mx+b... sooo that might help
2007-10-25 19:35:44 · answer #2 · answered by Kelsey 1 · 0⤊ 0⤋
im not doin ur homework 4 u...SORRY
2007-10-25 19:32:35 · answer #3 · answered by KiRbY<3 2 · 0⤊ 0⤋