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a)How many grams of calcium carbonate would be needed to react completely with 15.0 grams of the acid?
b) How many grams of carbon dioxide would be produced in this reaction?
c) How many grams of calcium chloride would be formed at the same time?

Formula: CaCO3 + 2HCl ----> CO2 +H2O + CaCl2

Im completely lostt and i hate stoichiometry! It seems so hard, so if you can help me, thank you very much! Include steps please!

2007-10-25 12:10:40 · 2 answers · asked by lalala 1 in Science & Mathematics Chemistry

2 answers

First convert known weight (grams) into moles (where I used <==> sign). Then based on the reaction equation, you know how many moles of reactant to be used and how many moles of products to be formed (where I used ==> sign). So in all rate, you need to calculate out the molar mass for each reactant and product (which I did not show and I believe you know how to).
a) 15.0 g HCl <==> 0.411 mol HCl ==> 0.206 mol CaCO3 <==> 20.6g CaCO3
b) 0.206 mol CaCO3 ==> 0.206 mol CO2 <==> 9.05g CO2
c) 0.206 mol CaCO3 ==> 0.206 mol CaCl2 <==> 22.8g CaCl2

2007-10-27 15:22:35 · answer #1 · answered by Hahaha 7 · 0 0

Any steel carbonate dropped at an acid will oftentimes produce carbon dioxide, so definite, the gasoline is carbon dioxide. i think you need to bubble it by means of lime water for extra info in spite of the incontrovertible fact that, if the lime water is going cloudy that is carbon dioxide.

2016-11-09 11:39:34 · answer #2 · answered by barreda 4 · 0 0

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