what is the volume occupied by 48.gms of so2 at stp?

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what is the volume occupied by 48.gms of so2 at stp?

2007-10-25 11:10:46 · 3 answers · asked by Alan G 1 in Science & Mathematics ➔ Chemistry

3 answers

Density of sulfur dioxide at STP = 2.551 g/L

Mass of sulfur dioxide given = 48 g

D=M/V
V=M/D
V= (48 g)/(2.551 g/L)
V = 18.8161 L
Volume to 2 sig figs = 19 L

2007-10-25 11:18:38 · answer #1 · answered by Stki 1 · 0⤊ 0⤋

48/64 x 24 litres

2007-10-25 18:15:57 · answer #2 · answered by Gervald F 7 · 0⤊ 0⤋

Atomic weights: S=32 O=16 SO2=80

48.0gSO2 x 1molSO2/80gSO2 x 22.4LSO2/1molSO2 = 13.4L to three significant figures

2007-10-25 18:17:24 · answer #3 · answered by steve_geo1 7 · 0⤊ 0⤋