Find 2 consecutive even integers such that twice the smallest is 26 less than 3 times the larger.
Find 3 consecutive integers such that twice the smallest is 12 more than largest.
those are the only problems that i needed help with. thanks so much.
2007-10-25 10:19:11 · 5 answers · asked by tom 1 in Education & Reference ➔ Homework Help
Here is the equation for the first:
2x + 26 = 3(x+2)
Solve for x, and x + 2
For the second:
2x - 12 = x + 2
Solve for x, and x + 1, and x + 2.
jmsloderb has the right answers; you can check your work from his. But the real trick is setting up and solving the equations.
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Cheers,
Bruce
2007-10-25 10:27:41 · answer #1 · answered by Bruce 7 · 0⤊ 0⤋
1+1 =2
2007-10-25 17:22:19 · answer #2 · answered by suryakant p 1 · 0⤊ 1⤋
1+1=2
2007-10-25 17:21:10 · answer #3 · answered by Anonymous · 0⤊ 2⤋
1. 20 and 22
20*2=40
22*3=66
66-40=26
2. 14, 15, 16
14*2=28
28-12=16
2007-10-25 17:24:04 · answer #4 · answered by jmsloderb 4 · 0⤊ 0⤋
the answer to your first problem is 23 and 24 the answer to your second question is 14,15,16
2007-10-25 17:31:07 · answer #5 · answered by Anonymous · 0⤊ 0⤋