x^2-x-56
It may seem simple but right now I'm stuck. An answer with a little explanation would do. Thanks a bunch guys. :)
2007-10-25 08:54:12 · 6 answers · asked by timmytommy92 1 in Science & Mathematics ➔ Mathematics
x² - x - 56 = 0
The middle term is - x
The first term x² = 1
Find the sum of the middle term
Multiply the first term 1 times the last terms - 56 equals - 56 and factor
Factors of - 56
1 x - 56
2 x - 28
4 x - 14
7 x - 8. . .←. .Use these factors
- 8 + 7 satifsy the sum of the middle term
Insert - 8x and + 7x into the equation
x² - x - 56 = 0
x² - 8x + 7x - 56 = 0
Group factor
(x² - 8x) + (7x - 56) = 0
x(x - 8) + 7(x - 8) = 0
(x + 7)(x - 8) = 0
- - - - - - - -s-
2007-10-25 09:17:38 · answer #1 · answered by SAMUEL D 7 · 0⤊ 0⤋
Notice that 7* (-8) is 56 but 7+ (-8) = -1
So x^2-x-56 = (x+7)(x-8)
2007-10-25 08:58:25 · answer #2 · answered by johnz622 2 · 0⤊ 0⤋
(x - 8)(x + 7)
2007-10-25 10:46:14 · answer #3 · answered by Como 7 · 0⤊ 0⤋
(x - 8)(x+7)
2007-10-25 09:13:56 · answer #4 · answered by james w 5 · 0⤊ 0⤋
(x+7)(x-8)
2007-10-25 08:58:51 · answer #5 · answered by Sheep Herder 3 · 0⤊ 0⤋
x^2-x-56=(x-8)(x+7)
2007-10-25 08:58:27 · answer #6 · answered by xandyone 5 · 0⤊ 0⤋