f(n) = n(n+1)/2
f(2) = 2*3 / 2 = 3
f(6) = 6*7 / 2 = 21
f(500) = 500 * 501 / 2 = 125250
2007-10-25 08:08:02
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answer #1
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answered by Puzzling 7
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This Site Might Help You.
RE:
Is there any mathematical formula for calculating the sum of consecutive numbers?
Is there any mathematical formula for calculating the sum of consecutive numbers? Like the sum os 1 to 2 is=3, the sum of 1 to 6 is=21,and the sum of 1 to 500 is= 125250. But, is there any formula to calculate and find these results instantly?
2015-08-19 00:55:42
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answer #2
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answered by Anonymous
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Sum Of Consecutive Numbers
2016-12-24 13:50:37
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answer #3
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answered by ? 4
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For the best answers, search on this site https://shorturl.im/axXgK
The sum of 1 + 3 + 5 + .. + x = (x + 1)^2 / 4 i.e. 1 + 3 + 5 = (5 + 1)^2 / 4 = 36/4 = 9 Now, if you wanted to sum 5 + 7 + 9, just use that formula twice. i.e. Sum 1 + 3 + 5 + 7 + 9, and then subtract the sum of 1 + 3 so (9+1)^2 / 4 - (3+1)^2/4 = 21 Hope this helps.
2016-04-07 02:10:04
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answer #4
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answered by Anonymous
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Sum Of Consecutive Integers
2016-09-28 06:42:29
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answer #5
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answered by Erika 4
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you can come up with your own formula pretty easily
the average of the top and bottom number multiplied by the average number.
This should work for consecutive numbers as well as multiples
EG
1, 2, 3, ...
2, 4, 6, 8, ...
1, 3, 5, 7, 9...
So long as the increase is linear multiplying the average of the top and bottom by the number of terms/numbers
2007-10-25 08:08:21
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answer #6
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answered by David F 5
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yes, there is:
sum = n (a1 + an) /2
n = number of terms (or how many numbers there are)
a1 = the first number
a2 = the last number
for example:
there are 500 numbers from 1 to 500
the first number si 1
the last number is 500
sum = 500 (1 + 500)/2
sum = 125,250
2007-10-25 08:09:32
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answer #7
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answered by Anonymous
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porky
2015-05-17 11:15:14
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answer #8
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answered by Anonymous
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