Can someone please help me solve the problem : -3[-2 the the 0 power-4)-(-2)(-3)]-[(-6 to the 0 power-2)-2 to the second power (-3)]
I know the answer is 24 but I don't know how to solve ,so PLEASE help!!!
2007-10-25 08:04:00 · 2 answers · asked by gaylegirl18 1 in Science & Mathematics ➔ Mathematics
You would use PEMDAS for order of operation you would respect Parentheses first, then Exponents, then Multiply and Divide, then Addition and Subtraction.
However, despite your careful attempt to explain the problem, I'm totally confused as to what is being raised to a power, what is being subtracted, etc. You have some mismatched and/or missing parentheses too.
Here's what I tried to understand:
-3[(-2^0 - 4)- (-2)(-3)] - [(-6^0 - 2) - 2² (-3)]
Exponents:
-3[(1 - 4)- (-2)(-3)] - [(1 - 2) - 4 (-3)]
Multiplication/Division:
-3[(1 - 4)- 6] - [(1 - 2) + 12 ]
Addition/Subtraction:
-3[-3 - 6] - [-1 + 12 ]
-3(-9) - (11)
27 - 11
16
Hmm...
Anyway, try PEMDAS order and see if you get 24.
2007-10-25 08:16:01 · answer #1 · answered by Puzzling 7 · 0⤊ 0⤋
go from what you have to:
[-3(-1-4)-(6)]-[(-1-2)-4(-3)] then:
[-3(-5)-6]-[-3+12] then:
(15-6)-(8) then:
9-8=1
your answer is 1, not 24
2007-10-25 08:23:39 · answer #2 · answered by Scottiegirl 2 · 0⤊ 0⤋