Three times the second of three consecutive integers is equal to five times the first.
2007-10-25 07:14:53 · 4 answers · asked by Sam o 1 in Science & Mathematics ➔ Mathematics
let n = 1st int
n+1 = 2nd int (since they are consecutive)
n+2 = 3rd
3*(n+1) = 5*n.
2007-10-25 07:18:41 · answer #1 · answered by Anonymous · 0⤊ 0⤋
Let x = the first integer.
The second integer is then (x+1)
So 3(x+1)=5(x)
This equation is correct however it has NO SOLUTIONS. The consecutive values will never work out to be two integers. When you solve for it you get a fraction which is by definition not an integer.
Hope this helps some!
2007-10-25 07:23:59 · answer #2 · answered by Shaun B 3 · 0⤊ 0⤋
X is the smallest integer.
3*(X+1) = 5X
2007-10-25 07:24:27 · answer #3 · answered by cattbarf 7 · 0⤊ 0⤋
3(x+1) = 5x
no answers to this problem.
2007-10-25 07:20:56 · answer #4 · answered by dave c 1 · 0⤊ 0⤋