Chemistry. Mole Stoichiometry help?

Question

How many moles of carbon monoxide gas are produced from the reaction of 5 mol of SnO2 (s) with 9 mol of carbon according to the equation below?

SnO2 (s) + 2C (s) --> Sn (s) + 2CO (g)

Answer 1

first find limiting reagent


according to the balanced reaction equation......

1 mole of SnO2 reacts with 2 moles C

so 5 moles SnO2 requires 10 moles C. and since you only 9 moles of C, C is the limiting reagent. (9 moles of C requires 4.5 moles SnO2 and you have 5 moles of SnO2. therefore you have excess SnO2)....

since you have 9 moles of C then from your balanced equation 2 moles C ---> 2 moles CO. So......

9 moles C x ( 2 moles CO / 2 moles C) = 9 moles CO

******Roger*****

...... I'm not sure where to begin dude.

yes 9 moles of C react with 9/2 moles SnO2. but. 1 mole of SnO2 ----> 2 moles of CO2. so 9/2 moles SnO2 ----> 2 x 9/2 moles CO = 9 moles CO. But it's easier to say 2 moles C ---> 2 moles of CO. So 9 moles of C ---> 9 moles of CO isn't it?

Answer 2

5 mol SnO2 would require 10 mol C. You don't have that. So 9 mol C is the limiting reagent: It will run out first.

9molC x 2molCO/2molC = 9 moles CO

Answer 3

4.5 moles

According to the equation, every mole of carbon will combine with half a mole of SnO2 to produce a mole of CO. This means 9 moles of carbon will combine with 9/2 moles of SnO2 to make 9/2 moles of CO. 5 moles of SnO2 were available, so 4.5 moles of CO were produced with half a mole of SnO2 left.

Answer 4

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Answer 5

first you need to desire to stability the reaction equation that is given; 2KClO3 -> 2K + 2ClO + 2O2 (decomposition reaction) for this reason, in accordance to the balanced reaction equation, the mole ratio between KClO3 and O2 is two:2 (or a million:a million in case you simplify.) for this reason, you're genuine - 15 mol of oxygen gasoline could be made out of 15 moles of KClO3. choose this helps:-D