Write 2ln(x)-5ln(x^3+1) as a logarithm of a single quantity?

Answer 1

ln {(x)^2/(x^3+1)^5}

Answer 2

2ln(x)-5ln(x^3+1)
= ln(x)^2 - ln(x^3 + 1)^5
= ln (x^2 / (x^3 + 1)^5 )

I used to properties of log that:
a logx = log x^a
and
log a - log b = log a/b

Answer 3

2 ln (x) - 5 ln (x^3 +1)

using the property blna = ln a^b;

ln (x^2) - ln [(x^3 +1)^5]

using the property lna-lnb = ln(a/b);

ln (x^2) / [(x^3+1)^5]

Answer 4

ln [(x^2)/(x^3 + 1)^5]

Answer 5

2 ln(x) - 5 ln(x^3+1)

ln(x)^2 - ln(x^3+1)^5 ----- (since a log b = log(b)^a)

ln[(x^2)/(x^3+1)^5] ------------(since log a - log b = log(a/b) )

Answer 6

i think its this:
ln(x^2)-ln(x^5(3x-1))
2-5(3x-1)
2-15x+5
-15x+7

Hope that helps.

Answer 7

Why on earth should I want to.

Answer 8

erm......