How would i factor this equation ?
1. 9x^2 = 16
2007-10-25 03:57:26 · 6 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
9x^2 - 16 = 0
(3x - 4) (3x + 4) = 0
x = - 4/3
x = 4/3
2007-10-25 04:03:01 · answer #1 · answered by Anonymous · 3⤊ 0⤋
9x^2 = 16
9x^2 - 16 = 0
Use this theorem to factor it:
(a^2 - b^2) = (a + b)(a - b)
So, 9x^2 - 16 = 0
(3x + 4)(3x - 4) = 0
x = ± (4/3)
2007-10-25 11:42:08 · answer #2 · answered by Anonymous · 0⤊ 0⤋
Isolate the x:
x² = (16/9)
Take the ± square root of each side:
x = ± â(16/9) = ± 4/3
So, x= 4/3 or x = -4/3
2007-10-25 11:02:02 · answer #3 · answered by MamaMia © 7 · 1⤊ 0⤋
9x²-16 = 0
(3x+4)(3x-4) = 0
x = 4/3 or -4/3
2007-10-25 12:17:24 · answer #4 · answered by steiner1745 7 · 0⤊ 0⤋
Get constants on one side, variables on the other. You do this by dividing both sides by 9:
x^2=16/9
Then take the square root:
x=+/- 4/3
Don't forget the +/- (there are two roots)!
2007-10-25 11:11:36 · answer #5 · answered by Amelia 6 · 1⤊ 0⤋
first square root both side of the equations which gets rid of the exponet on the left then divide 9 then bam u got the answer
2007-10-25 11:01:44 · answer #6 · answered by MR. I KNOW EVERYTHING 2 · 0⤊ 0⤋